- In accordance with the pressure gradient quizlet Patch#
- In accordance with the pressure gradient quizlet Pc#
Then the tire has the same deflection as when maximum load and pressure needed for that on the tire. then the real load on tire is about that 1 to 15% of the maximum load given on tire. So its possible that the total load on a tire is only carried by the construction of the tire. So if you would then determine the surface on ground by the number of nails depressed and compare that with normal underground, the calculated surface will be the same.
In accordance with the pressure gradient quizlet Pc#
12 Review 7 (1) Unit 8 PC MC B (2) Practice Test 2018 8 APUSH (1) Unit 9 PC. Then if you would determine the surface on the ground and multiply it with the over-pressure the load on it calculated is lower then the real load on tire.įor truck tire difference is small ( probably that 1% construction load, as I babtised it), but for normal car tire difference will be about 5 to 15%.Įven the profile makes the pressure on ground higher, and if you would place the tire on a blunt nail bed the tire bends the same and by that the pressure on the nails will be much higher. Details: ap lang unit 5 progress check mcq answers quizlet. I estimate that part to be about between 5 and 15 % of the maximum load of a normal car tire, but can go as low as 1% of that for a Truck tire with high pressure. So pressure on the ground is higher then the over-pressure inside the tire. Part of the load on a tire is supported by the construction of the tire at the actual deflection of it. I suspect the only way to get an idea of what $F_e$ is would be to measure it. I think it would be very hard to predict the elastic force caused by the tyre deformation from first principles. So the pressure at the tyre/ground contact is greater than the tyre pressure by $F_e/A$. So the weight of the car deforms the tyre and this deformation of the tyre also creates an elastic force in a Hooke's law sort of way. If you've ever handled a tyre that is off the wheel you'll know that it can support a considerable load even when uninflated (though obviously far less than the weight of a car).
In accordance with the pressure gradient quizlet Patch#
If the area of the contact patch is $A$ then the air inside the tyre exerts a force on the ground of $F_i = P_iA$.īut the tyre itself has some elasticity. The pressure everywhere inside the tyre is the same - let's calls this $P_i$.
No, the pressure inside the tyre is slightly less than the pressure at the tyre/ground interface.
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